X=17x^2+3x

Solution for X=17x^2+3x equation:

X=17X^2+3X

We move all terms to the left:

X-(17X^2+3X)=0

We get rid of parentheses

-17X^2+X-3X=0

We add all the numbers together, and all the variables

-17X^2-2X=0

a = -17; b = -2; c = 0;
Δ = b2-4ac
Δ = -22-4·(-17)·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-2}{2*-17}=\frac{0}{-34}
=0
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+2}{2*-17}=\frac{4}{-34}
=-2/17
$